Torsion of Circular Shaft Problem
In this worked example, a stepped solid circular shaft made of A284 Grade C steel transmits
7000 Nm torque at 900 rpm from a turbine to a generator. Using the torsion relation
τ = T·c / J and standard yield criteria for ductile materials in plane stress, we determine
the maximum shear stress, principal stresses, and check whether the shaft design is safe.
The stepped shaft shown in the figure is to rotate at 900 rpm as it transmits 7000 Nm
torque from a turbine to a generator and this is the only loading case on the shaft.
The material specified in the design is A284 Steel (grade C) and the design factor is 2.
Determine/evaluate the following for the shaft:
a) Maximum shear stress on the shaft
b) Principal stresses on the shaft
c) Material yield criteria for the selected material and the resulting stresses.
Solution of the Torsion Problem for Circular Shaft
Step 1 – Input parameters and material properties
Write down the input parameters (including material properties) which are
defined in the sample example.
|
INPUT PROPERTIES SUMMARY
|
|
Parameter
|
Value
|
|
Diameter of larger shaft section [D]
|
100 |
mm |
|
Diameter of smaller shaft section [d]
|
50 |
mm |
|
Radius of smaller shaft section [c2]
|
25 |
mm |
|
Torque [T]
|
7000 |
Nm |
|
Rotation speed [ω]
|
900 |
rpm |
|
Design factor [nd]
|
2 |
--- |
|
Yield strength (A284 Steel, Grade C) [Sy]
|
205 |
MPa |
|
Elastic modulus (A284 Steel) [E]
|
200 |
GPa |
|
Shear (rigidity) modulus (A284 Steel) [G]
|
80 |
GPa |
|
Elongation at break (A284 Steel) [εbrk]
|
21% |
--- |
Step 2 – Maximum shear stress and angle of twist
Go to the
"
Torsion of Solid and Hollow Shafts Calculator
"
page to calculate the maximum shear stress on the shaft. Larger shear stresses occur on the smaller
diameter section of the shaft, so analysis of the smaller diameter section is sufficient for this example.
|
RESULTS
|
|
Parameter
|
Value
|
|
Maximum shear stress [τmax]
|
285.206
|
MPa |
|
Angle of twist [θ]
|
4.085
|
deg |
|
Power requirement [P]
|
659.734
|
kW |
|
Polar moment of inertia [J]
|
613592.312
|
mm4 |
Step 3 – Stress concentration at shaft shoulder fillet
There is a shoulder fillet in the shaft design and this geometry will
raise the local stress. The stress concentration factor and the maximum shear stress
at the shoulder fillet are calculated for torsional loading. Go to the
"
Shoulder fillet in stepped circular shaft
"
page for calculations.
|
LOADING TYPE - TORSION
|
|
Parameter
|
Value
|
|
Stress concentration factor
|
1.25
|
--- |
|
Nominal shear stress at shaft
|
285.21
|
MPa |
|
Maximum shear stress due to torsion
|
357.03
|
The maximum shear stress of 357 MPa occurs at the outer radius of the shoulder
fillet. This is the answer for clause a) of the sample example.
Step 4 – Principal stresses at the shaft surface
To calculate the principal stresses occurring on the shaft surface, go to the
"
Principal/Maximum Shear Stress Calculator For Plane Stress
"
page. Note that the torsional loading of the shaft results in a plane stress state
on the surface of the shaft, so this calculator can be used.
|
RESULTS
|
|
Parameter
|
Value
|
|
Maximum principal stress
|
357
|
MPa
|
|
Minimum principal stress
|
-357
|
|
Maximum shear stress*
|
357
|
|
Average principal stress
|
0
|
|
Von Mises stress
|
618.3
|
|
Angle of principal stresses**
|
45
|
deg
|
|
Angle of maximum shear stress**
|
0
|
The principal stresses are calculated as 357 MPa and -357 MPa. This is the
answer for clause b) of the sample example.
Step 5 – Yield criteria for ductile material under plane stress
The selected material (A284 Steel) is ductile since the elongation at break is
greater than 5%. For the evaluation of yield criteria for a ductile material
with a plane stress state, we can use the
"
Yield Criteria For Ductile Materials Under Plane Stress (Static Loading)
"
page.
|
RESULTS
|
|
Parameter
|
Condition to be met for safe design
|
Status
|
|
MSS (Maximum Shear Stress, Tresca) theory
|
(σmax - σmin) < Sy / n
|
714 < 102.5
|
Not OK
|
|
DE (Distortion Energy, von Mises) theory
|
(σmax2 - σmax·σmin + σmin2)0.5 < Sy / n
|
618.3 < 102.5
|
Not OK
|
Summary
According to the results, the design is not
safe for the given parameters and conditions. The shaft diameter and/or material
must be changed to satisfy the required design criteria. The steps listed above shall
be repeated to find dimensions or materials that satisfy the required conditions.
Note: In this example, the loading case
is static and the shaft material is ductile. According to
Shigley's Mechanical Engineering Design
Chapter 3, for ductile materials in static loading, the stress-concentration factor is not usually applied to predict the
critical stress, because plastic strain in the region of the stress is localized and
has a strengthening effect.
According to
Peterson's Stress Concentration Factors
Chapter 1, the notch sensitivity q usually lies in the range of 0 to 0.1 for
ductile materials. If a statically loaded member is also subjected to shock
loading or subjected to high and low temperature, or if the part contains sharp
discontinuities, a ductile material may behave like a brittle material. These
are special cases and if there is a doubt, Kt (q = 1) shall be applied.
In this example, since there is no information
about temperature and shock loading conditions of the shaft,
the notch sensitivity factor q is taken as 1 and Kt is applied.
Related calculators used in this example
The problem is fully solved with the following calculators:
Frequently Asked Questions
Is the shaft design safe for the given loading?
No. For the given torque, geometry, and A284 Grade C steel with a design factor of 2,
both the Maximum Shear Stress (Tresca) and Distortion Energy (von Mises) criteria are not satisfied,
so the design is not safe.
What causes the highest stress in this shaft?
The highest stress occurs at the shoulder fillet of the stepped shaft, where the geometry change
introduces a stress concentration under torsional loading.
How can I make the shaft design safe?
You can increase the shaft diameter, select a stronger material with a higher yield strength,
or reduce the applied torque. After each change, repeat the calculations to verify
the design against the selected yield criteria.