# ROUND PIN JOINT WITH CLOSELY FITTING PIN IN A FINITE-WIDTH PLATE

Round pin joint with closely fitting pin in a finite width plate. Stress concentration factors (Kt) calculator for tension loads.

 INPUT PARAMETERS Parameter Value Plate width [D] mm cm m inch ft Hole diameter [d] Hole center to plate edge distance [L] Plate thickness [h] Tension force [P] N kN lbf

Note: Use dot "." as decimal separator.

 RESULTS LOADING TYPE - TENSION Parameter Value TENSION STRESS Stress concentration factor [Kta] * --- --- Nominal tension stress based on net section [σna ] o --- MPa psi ksi Maximum tension stress [σmax] --- BEARING STRESS Stress concentration factor [Ktb] ** --- --- Nominal bearing stress based on bearing area [σnb ] x --- MPa psi ksi Maximum bearing stress [σmax ] ---

Note 1: * Geometry rises σna by a factor of Kta. (Kta= σmaxna)

Note 2: ** Geometry rises σnb by a factor of Ktb. (Ktb= σmaxnb)

Note 3: o Nominal stress based on net section (σna= P/[(D-d)h])

Note 4: x Nominal stress based on bearing area  (σnb= P/(dh))

### Definitions:

Stress Concentration Factor: Dimensional changes and discontinuities of a member in a loaded structure causes variations of stress and high stresses concentrate near these dimensional changes. This situation of high stresses near dimensional changes and discontinuities of a member (holes, sharp corners, cracks etc.) is called stress concentration. The ratio of peak stress near stress riser to average stress over the member is called stress concentration factor.

Kt: Theoretical stress concentration factor in elastic range = (σmaxnom)

### Formulas:

 Tension For $$0.15\le \frac { d }{ D } \le 0.75,\quad \frac { L }{ D } \ge 1$$ $${ K }_{ ta }=12.882-52.714\frac { d }{ D } +89.762{ (\frac { d }{ D } ) }^{ 2 }-51.667{ (\frac { d }{ D } ) }^{ 3 }$$ $${ K }_{ tb }=0.2880+8.820\frac { d }{ D } -23.196{ (\frac { d }{ D } ) }^{ 2 }+29.167{ (\frac { d }{ D } ) }^{ 3 }$$ Nominal stress based on net section:  $${ \sigma }_{ na }=P/(D-d)h$$ Nominal stress based on bearing area: $${ \sigma }_{ nb }=P/dh$$ $${ \sigma }_{ max\_ a }={ K }_{ t }{ \sigma }_{ na }$$ $${ \sigma }_{ max\_ b }={ K }_{ t }{ \sigma }_{ nb }$$