ROUND PIN JOINT WITH CLOSELY FITTING PIN IN A FINITE-WIDTH PLATE

Round pin joint with closely fitting pin in a finite width plate. Stress concentration factors (Kt) calculator for tension loads.

Stress concentration factor for round pin joint with closely fitting pin in finite-width plate
 INPUT PARAMETERS
Parameter Value
Plate width [D]
Hole diameter [d]
Hole center to plate edge distance [L]
Plate thickness [h]
Tension force [P]

Note: Use dot "." as decimal separator.


 RESULTS
LOADING TYPE - TENSION
Stress concentration factor for round pin joint with closely fitting pin in finite-width plate under tension
Parameter Value
TENSION STRESS
Stress concentration factor [Kta] * --- ---
Nominal tension stress based on net section [σna ] o ---
Maximum tension stress [σmax] ---
BEARING STRESS
Stress concentration factor [Ktb] ** --- ---
Nominal bearing stress based on bearing area [σnb ] x ---
Maximum bearing stress [σmax ] ---

Note 1: * Geometry rises σna by a factor of Kta. (Kta= σmax/σna)

Note 2: ** Geometry rises σnb by a factor of Ktb. (Ktb= σmax/σnb)

Note 3: o Nominal stress based on net section (σna= P/[(D-d)h])

Note 4: x Nominal stress based on bearing area  (σnb= P/(dh))


Definitions:

Stress Concentration Factor: Dimensional changes and discontinuities of a member in a loaded structure causes variations of stress and high stresses concentrate near these dimensional changes. This situation of high stresses near dimensional changes and discontinuities of a member (holes, sharp corners, cracks etc.) is called stress concentration. The ratio of peak stress near stress riser to average stress over the member is called stress concentration factor.

Kt: Theoretical stress concentration factor in elastic range = (σmax/σnom)

Formulas:

Stress concentration factor for round pin joint with closely fitting pin in finite-width plate
Tension
Stress concentration factor for round pin joint with closely fitting pin in finite-width plate under tension
For $$0.15\le \frac { d }{ D } \le 0.75,\quad \frac { L }{ D } \ge 1$$
$${ K }_{ ta }=12.882-52.714\frac { d }{ D } +89.762{ (\frac { d }{ D } ) }^{ 2 }-51.667{ (\frac { d }{ D } ) }^{ 3 }$$
$${ K }_{ tb }=0.2880+8.820\frac { d }{ D } -23.196{ (\frac { d }{ D } ) }^{ 2 }+29.167{ (\frac { d }{ D } ) }^{ 3 }$$
Nominal stress based on net section: 
$${ \sigma }_{ na }=P/(D-d)h$$
Nominal stress based on bearing area:
$${ \sigma }_{ nb }=P/dh$$
$${ \sigma }_{ max\_ a }={ K }_{ t }{ \sigma }_{ na }$$
$${ \sigma }_{ max\_ b }={ K }_{ t }{ \sigma }_{ nb }$$

Reference: